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JEE Main 9 Apr 2019 Paper 1 Solved Paper

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Question : 10

Total: 90

The electric field of light wave is given as

=10−3‌cos‌ (

−2π×6×1014t )‌

. The light falls on a metal plate of work function 2eV. The stopping potential of the photo-electrons is:Given, E (in eV) =

0.48 V
2.48 V
0.72V
2.0

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