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JEE Main 9 Apr 2019 Paper 2 Solved Paper
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© examsnet.com
Question : 28
Total: 90
A metal wire of resistance 3Ω is elongated to make a uniform wire of double its previous length. This new wire is now bent and the ends joined to make a circle. If two points on this circle make an angle 60° at the centre, the equivalent resistance between these two points will be:
5
2
Ω
5
3
Ω
12
5
Ω
7
2
Ω
Validate
Solution:
R
=
∂
L
A
=
∂
L
2
V
R
∝
L
2
After doubling
R
=
12
Ω
For
A
.
B
wire
R
∝
L
Parallel
1
R
e
f
f
=
1
2
+
1
10
=
3
5
R
e
f
f
=
5
3
Ω
© examsnet.com
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