Test Index

JEE Main 9 Apr 2019 Paper 2 Solved Paper

© examsnet.com

Question : 6

Total: 90

In a conductor, if the number of conduction electrons per unit volume is 8.5×1028m−3 and mean free time is 25 fs (femto second), it’s approximate resistivity is: (me=9.1×10−31)

10−8Ωm
10−6Ωm
10−5Ωm
10−7Ωm

Go to Question:

Prev Question

Next Question