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JEE Main 9 Jan 2019 Shift 2 Solved Paper
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© examsnet.com
Question : 15
Total: 90
The energy associated with electric field is (
U
E
)and with magnetic field is (
U
B
) for anelectromagnetic wave in free space. Then :
U
E
=
U
B
2
U
E
<
U
B
U
E
=
U
B
U
E
>
U
B
Validate
Solution:
Average energy density of magnetic field,
u
B
=
B
0
2
2
µ
0
,
B
0
is maximum value of magneticfield.
Average energy density of electric field,
u
E
=
ε
0
∊
0
2
2
now ,
∊
0
= C
B
0
,
C
2
=
1
µ
0
∊
0
u
E
=
∊
0
/
2
×
C
2
B
0
2
=
∊
0
/
2
×
1
µ
0
∊
0
×
B
0
2
=
B
0
2
2
µ
0
=
u
B
u
E
=
u
B
since energy density of electric & magneticfield is same, energy associated with equalvolume will be equal.
u
E
=
u
B
© examsnet.com
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