Equation of family of circle touching y-axis at (0, 4) is given by (x−0)2+(y−4)2+λx=0. It passes through (2, 0) ⇒λ=−10. ⇒ Required circle is (x−0)2+(y−4)2−10x=0 ⇒x2+y2−10x−8y+16=0 center of circle = (5,4) and radius = 5 distance of 4x + 3y - 8 = 0 from (5, 4) =|