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JEE Main 9 Jan 2020 Shift 2 Solved Paper
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© examsnet.com
Question : 10
Total: 75
There is a small source of light at some depth below the surface of water (refractive index =
4
3
) in a tank of large cross sectional surface area. Neglecting any reflection from the bottom and absorption by water, percentage of light that emerges out of surface is (nearly) : [Use the fact that surface area of a spherical cap of height h and radius of curvature r is 2 πrh]:
17%
21%
34%
50%
Validate
Solution:
4
3
sin
θ
=
1
sin
90
°
sin
θ
=
3
4
Area of sphere in which light spread
=
4
π
R
2
Ω
=
2
π
(
1
−
cos
θ
)
Ω
=
2
π
(
1
−
√
7
4
)
P → 4π steradians
P
′
=
P
4
π
(
1
−
cos
θ
)
Ratio
=
P
′
P
=
2
π
(
1
−
cos
θ
)
4
π
=
1
−
√
7
4
2
=
0.17
© examsnet.com
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