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JEE Main 9 Jan 2020 Shift 2 Solved Paper

Section: Mathematics

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Question : 55

Total: 75

Let a, b ∈ R, a ≠ 0 be such that the equation, ax2−2bx+5=0 has a repeated root a, which is also a root of the equation, x2−2bx−10=0. If P is the other root of this equation, then α2+β2 is equal to :

[9 Jan 2020 Shift 2]

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