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JEE Main Chemistry Class 11 Structure of Atom Part 1 Questions
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© examsnet.com
Question : 30
Total: 100
What is the work function of the metal if the light of wavelength
4000
Å
generates photoelectrons of velocity
6
×
10
5
m
s
−
1
from it ?
(Mass of electron
=
9
×
10
−
31
k
g
Velocity of light
=
3
×
10
8
m
s
−
1
Planck's constant
=
6.626
×
10
−
34
J
s
Charge of electron
=
1.6
×
10
−
19
J
e
V
−
1
)
[Jan. 12, 2019 (I)]
0.9
e
V
3.1
e
V
2.1
e
V
4.0
e
V
Validate
Solution:
E
=
h
v
=
h
c
λ
E
=
6.626
×
10
−
34
×
3
×
10
8
4000
×
10
−
10
=
4.97
×
10
−
19
J
=
4.97
×
10
−
19
J
1.6
×
10
−
10
J
e
V
−
1
=
3.1
e
V
K
E
=
1
2
m
v
2
=
1
2
×
9
×
10
−
31
k
g
×
(
6
×
10
5
m
s
−
1
)
2
=
1.62
×
10
−
19
J
[
1
J
=
k
g
⋅
m
2
s
−
2
]
=
1
c
V
According to photoelectric effect,
K
.
E
.
=
h
v
−
h
v
0
h
v
0
=
h
v
−
K
.
E
Work function
(
W
0
)
=
E
−
K
.
E
=
3.1
−
1
=
2.1
e
V
© examsnet.com
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