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JEE Main Chemistry Class 11 Structure of Atom Part 1 Questions
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© examsnet.com
Question : 56
Total: 100
At temperature
T
, the average kinetic energy of any particle is
3
2
k
T
. The de Broglie wavelength follows the order :
[Online April 11, 2015]
Visible photon
>
Thermal neutron
>
Thermal electron
Thermal proton
>
Thermal electron
>
Visible photon
Thermal proton
>
Visible photon
>
Thermal electron
Visible photon
>
Thermal electron
>
Thermal neutron
Validate
Solution:
Kinetic energy of any particle
=
3
2
k
T
Also
K
.
E
.
=
1
2
m
v
2
1
2
m
v
2
=
3
2
k
T
⇒
v
2
=
3
k
T
m
v
=
√
3
k
T
m
de-broglie wavelength
=
λ
=
h
m
v
=
h
m
√
3
k
T
m
λ
=
h
√
3
k
T
m
;
λ
∝
1
√
m
Mass of electron
<
mass of neutron
λ
(electron )
>
λ
(neutron)
© examsnet.com
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