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Test Index
Chemical Bonding and Molecular Structure Part 3
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Section:
Chemistry
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© examsnet.com
Question : 22
Total: 43
Total number of electron present in
(
Ï€
*
)
molecular orbitals of
O
2
,
O
2
+
and
O
2
−
is ______.
[9 Apr 2024 Shift 2]
Your Answer:
Validate
Solution:
‌
O
2
(
16
e
)
:
(
σ
1
s
)
2
(
σ
1
s
*
)
2
(
σ
2
s
)
2
(
σ
2
s
*
)
2
‌
(
σ
2
p
)
2
[
(
Ï€
2
p
)
2
=
(
Ï€
2
p
)
2
]
,
[
(
Ï€
2
p
*
)
1
=
(
Ï€
2
p
*
)
1
]
Number of
e
−
present in
(
Ï€
*
)
of
O
2
=
2
Number of
e
−
present in
(
Ï€
*
)
of
O
2
+
=
1
Number of
e
−
present in
(
Ï€
*
)
of
O
2
−
=
3
So total
e
−
in
(
Ï€
*
)
=
2
+
1
+
3
=
6
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