Hydrocarbons Part 2

Concept:Catalytic hydrogenation with $\mathrm{Pd/C}$ gives syn addition, producing cis-alkenes.Dissolving metal reduction with $\mathrm{Na/liq\ NH_3}$ gives anti addition, producing trans-alkenes.Explanation:But-2-yne ($\mathrm{CH_3C \equiv CCH_3}$) is treated separately:(i) $\mathrm{H_2/Pd/C}$: syn addition of two H atoms yields cis-2-butene (X).(ii) $\mathrm{Na/liq\ NH_3}$: anti addition via radical intermediate yields trans-2-butene (Y).Now analyze each statement:A. X and Y are stereoisomers – yes, they are cis-trans isomers. Hence correct.B. Dipole moment of X is zero – false, cis-2-butene has a net dipole moment because both methyl groups are on same side. Hence incorrect.C. Boiling point of X is higher than Y – true, cis isomer is more polar and has higher boiling point. Hence correct.D. X and Y react with $\mathrm{O_3/Zn + H_2O}$ to give different products – false, both yield acetaldehyde ($\mathrm{CH_3CHO}$) as the only carbonyl product. Hence incorrect.Thus the incorrect statements are B and D.Answer:Option A: B and D Only