p Block Elements Part 3

Concept:Amphoteric oxides react with both acids and bases. Lewis acids accept electron pairs to form coordinate bonds.Explanation:For Statement I, examine each pair of oxides from Group 14 elements.$[\mathrm{SiO}_2, \mathrm{CO}_2]$: both are acidic oxides (not amphoteric).$[\mathrm{SnO}, \mathrm{SnO}_2]$: both are amphoteric oxides.$[\mathrm{PbO}, \mathrm{PbO}_2]$: both are amphoteric oxides.$[\mathrm{GeO}, \mathrm{GeO}_2]$: both are acidic oxides (not amphoteric).Only pairs 2 and 3 contain oxides that are both amphoteric.Thus, the number of such pairs is 2. Statement I is correct.For Statement II: In $\mathrm{BF}_3$, boron has only six valence electrons, making it electron-deficient. It acts as a Lewis acid by accepting a lone pair from $\mathrm{NH}_3$, forming an adduct. The boron atom is $\mathrm{sp}^2$ hybridised, giving a trigonal planar geometry. All these points are true. Statement II is correct.Answer:Both Statement I and Statement II are true. Hence, the correct option is C.