‌‌‌Z−2A−4Y And the formula for β is - ‌ZAX→‌Z−1‌AY Now for the given above question we see that, - ‌92238M‌
−2α
→
‌92−4238−8N ‌
‌X
Y
X−2β+→‌86230L Therefore we can now calculate the number of neutrons in L,- L=230−86 L=144 So, as we can see the no. of neutrons present in L is 144 .