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Test Index
Electro Chemistry Part 3
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Section:
Chemistry
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Question : 2 of 25
Marks:
+1
,
-0
For a general redox reaction
Anode :
R
e
d
1
→
O
x
1
n
1
+
+
n
1
e
−
\mathrm{Red}_1 \rightarrow \mathrm{Ox}_1^{n_1^{+}} + n_1 e^{-}
Red
1
→
Ox
1
n
1
+
+
n
1
e
−
Cathode :
O
x
2
+
n
2
e
−
→
R
e
d
2
n
2
−
\mathrm{Ox}_2 + n_2 e^{-} \rightarrow \mathrm{Red}_2^{n_2^{-}}
Ox
2
+
n
2
e
−
→
Red
2
n
2
−
Which of the following statement is incorrect?
[JEE Main 6 Apr 2026 shift 2]
The overall reaction can be written as
n
2
R
e
d
1
+
n
1
O
x
2
⇌
n
2
O
x
1
n
1
+
+
n
1
R
e
d
2
n
2
−
n_2 \mathrm{Red}_1 + n_1 \mathrm{Ox}_2 \rightleftharpoons n_2 \mathrm{Ox}_1^{n_1^{+}} + n_1 \mathrm{Red}_2^{n_2^{-}}
n
2
Red
1
+
n
1
Ox
2
⇌
n
2
Ox
1
n
1
+
+
n
1
Red
2
n
2
−
The electrons do not appear in the overall reaction because electrons produced at the anode are consumed at the cathode.
Here n is the number of electrons transferred in redox reaction.
If the reaction is carried out reversibly, the electrical work done is equal to the ratio of charge and potential difference through which charge is moved.
Validate
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