GivenEZn2+/Zn∘=−0.76VEAg+/Ag∘=+0.80VAt 298 KEcell=1.60VEcell∘=Ecathode∘−Eanode∘=0.80−(−0.76)=1.56VZn+2Ag+⟶Zn2++2AgSo,n=2Ecell=Ecell∘−20.059logQ.......(1)Q=[Ag+]2[Zn2+]=x21…(2)Put value of (2) in (1)1.60=1.56−20.059log(x21)1.60=1.56+20.059×2logx⟶1.60=1.56+0.059logx0.04=0.059logx10gx=0.0590.04=5.94