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JEE Main Math Class 11 Coordinate Geometry Part 3 Questions
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© examsnet.com
Question : 30
Total: 100
If one of the diameters of the circle
x
2
+
y
2
−
2
x
−
6
y
+
6
=
0
is a chord of another circle '
C
', whose centre is at
(
2
,
1
)
, then its radius is
[2021, 24 Feb. Shift-I]
Your Answer:
Validate
Solution:
Given, circle
⇒
x
2
+
y
2
−
2
x
−
6
y
+
6
=
0
Coordinate of
C
=
(
1
,
3
)
Radius
=
r
=
√
1
2
+
3
2
−
6
=
√
4
=
2
units
C
D
=
√
(
2
−
1
)
2
+
(
1
−
3
)
2
=
√
1
+
4
=
√
5
Now, by using Pythagoras theorem in
△
A
D
C
,
A
C
2
=
A
D
2
+
C
D
2
=
(
2
)
2
+
(
√
5
)
2
=
4
+
5
A
C
2
=
9
A
C
=
√
9
=
3
∴
Required radius
=
3
© examsnet.com
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