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JEE Main Math Class 11 Coordinate Geometry Part 3 Questions
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© examsnet.com
Question : 32
Total: 100
Consider the parabola with vertex
(
1
2
,
3
4
)
and the directrix
y
=
1
2
. Let
P
be the point where the parabola meets the line
x
=
−
1
2
. If the normal to the parabola at
P
intersects the parabola again at the point 0 , then
(
P
Q
)
2
is equal to
[2021, 01 Sep. Shift-11]
75
8
125
16
25
2
15
2
Validate
Solution:
Vertex
(
1
2
,
3
4
)
Equation of directrix
y
=
1
2
Equation of parabola is
(
x
−
1
2
)
2
=
y
−
3
4
Point on parabola
P
(
−
1
2
,
7
4
)
Equation of normal at
P
(
−
1
2
,
7
4
)
is
x
=
2
y
−
4
This normal cuts the parabola at
Q
(
2
,
3
)
(
P
Q
)
2
=
(
2
+
1
2
)
2
+
(
3
−
7
4
)
2
=
125
16
© examsnet.com
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