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JEE Main Math Class 11 Coordinate Geometry Part 4 Questions
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© examsnet.com
Question : 7
Total: 100
Let
A
=
{
(
x
,
y
)
∈
ℝ
2
:
y
≥
0
,
2
x
≤
y
≤
√
4
−
(
x
−
1
)
2
}
and
B
=
{
(
x
,
y
)
∈
ℝ
×
ℝ
:
0
≤
y
≤
min
{
2
x
,
√
4
−
(
x
−
1
)
2
}
}
Then the ratio of the area of
A
to the area of
B
is
[29-Jan-2023 Shift 1]
π
−
1
π
+
1
π
π
−
1
π
π
+
1
π
+
1
π
−
1
Validate
Solution:
y
2
+
(
x
−
1
)
2
=
4
shaded portion
=
circular
(
OABC
)
−
Ar
(
∆
OAB
)
=
π
(
4
)
4
−
1
2
(
2
)
(
1
)
A
=
(
π
−
1
)
Area
B
=
Ar
(
△
AOB
)
+
Area of arc of circle
(
ABC
)
=
1
2
(
1
)
(
2
)
+
π
(
2
)
2
4
=
π
+
1
A
B
=
π
−
1
π
+
1
© examsnet.com
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