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Binomial Theorem Part 3

Section: Mathematics

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Question : 2

Total: 45

The sum of the coefficients of x499 and x500 in (1+x)1000+x(1+x)999+x2(1+x)998+...+x1000 is :

[28 Jan 2026 Shift 2]

‌1002C501
‌1001C501
‌1000C501
‌1002C500

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