Equation of line AB is 3y−x=2 And AC is x+y=2 In line AB, When y=0,x=−2 ∴‌‌B(−2,0) In line AC, When y=0,x=2 ∴‌‌C(2x,0) Equation of altitude of BC, Y=x+2 Similarly, equation of altitude of AB, y=−3x+6 ∴‌‌ On solving, orthocentre P(1,3) ∴‌‌ar(△PBC)=6