−2x−6=0 ‌x2−4x−12=0 ‌x2−6x+2x−12=0 ‌x(x−6)+2(x−6)=0 ‌(x−6)(x+2)=0 Point of intersection are (6,18) and (−2,2)(−2,2) is in second quadrant ‌a=−2,b=2 ‌I=∫−22‌
9x2
1+5x
‌dx⋅⋅⋅⋅⋅⋅⋅(i) I=∫−22‌
9x2
1+5−x
‌dx‌‌‌⋅⋅⋅⋅⋅⋅⋅(ii) Adding (i) and (ii) ‌2I=∫−229x2‌dx ‌I=9‌