=e2∕3+ln3−ln|X|>0 ln|X|<(e2∕3+ln3) Let λ=(e2∕3+ln3) |x+2|<eλ −eλ<x+2<eλ −eλ−2<x<eλ−2 α+β=−4⇒|α+β|=4 Although x=−2 should be excluded from domain but according to the given problem it will the most appropriate solution.