] may be discontinuous on x∈[0,4] are ‌=1,2,3,4,5,6,7,8 ‌x=√2,2,√6,2√2,√10,2√3,√14,4 And for [sqrt‌x] corresponding values are x=1,2 On checking for continuity at these points we get the f(x) is discontinuous at x=1,√2,2,√6,2√2,√10,2√3,√14 Hence, f(x) is discontinuous for 8 values of x∈[0,4]