Test Index

Probability Part 1

Section: Mathematics

Question : 16 of 100

Marks: +1, -0

3,3,4,4,4,5,5

Solution:

Given, digits 3, 3, 4, 4, 4, 5, 5 Total 7 digit number from given digits will be

\;\frac{7!}{3!2!2!} \;\; = \;\frac{7\times6\times5\times4}{2\times2}

\;\; =210

Now, if the 7 digit number is divisible by 2 , then last digit must be 4 . Now, 7 digit number divisible by 2 will be

=\;\frac{6!}{2!2!2!}=\;\frac{6\times5\times4\times3}{2\times2}=90

Required probability

=\;\frac{90}{210}=\;\frac{9}{21}=\;\frac{3}{7}

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