lie in the plane x+3y−αz+β=0 ∴Pt(2,1,−2) lies on the plane i.e. 2+3+2α+β=0 or 2α+β+5=0......(i) Also normal to plane will be perpendicular to line, ‌∴3×1−5×3+2×(−α)=0 ‌⇒α=−6 From equation (i) then, β=7 ∴(α,β)=(−6,7)