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JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 3 Questions
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© examsnet.com
Question : 11
Total: 100
There is an air bubble of radius
1.0
mm
in a liquid of surface tension
0.075
nm
−
1
and density
1000
kg
m
−
3
at a depth of
10
cm
below the free surface. The amount by which the pressure inside the bubble is greater than the atmospheric pressure is ________
Pa
(
g
=
10
ms
−
2
)
[15-Apr-2023 shift 1]
Your Answer:
Validate
Solution:
P
i
n
=
P
0
+
ρ
g
h
+
2
T
r
P
in
−
P
0
=
1000
×
10
×
0.1
+
2
×
0.075
0.001
=
1000
+
150
P
in
−
P
0
=
1150
Pa
© examsnet.com
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