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Test Index
JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 3 Questions
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© examsnet.com
Question : 24
Total: 100
A body cools from
80
∘
C
to
60
∘
C
in 5 minutes. The temperature of the surrounding is
20
∘
C
. The time it takes to cool from
60
∘
C
to
40
∘
C
is:
[12-Apr-2023 shift 1]
450
s
500
s
420
s
25
3
s
Validate
Solution:
Body cools from
80
∘
C
to
60
∘
C
in
5
min
T
suroumding
=
20
∘
C
Time taken to cool from
60
∘
C
to
40
∘
C
?
we know newton's law of cooling is
−
d
θ
dt
=
b
(
θ
−
θ
0
)
surrounding temp.
We take approx value of
v
as
80
+
60
2
=
70
∘
20
5
=
b
[
70
−
20
]
. . . (1)
20
t
=
b
[
50
−
20
]
. . . (2)
After solving
t
=
25
3
min
In second
t
=
25
3
×
60
=
500
s
e
c
.
© examsnet.com
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