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JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 3 Questions
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© examsnet.com
Question : 99
Total: 100
As per the given figure, two plates
A
and
B
of thermal conductivity
K
and
2
K
are joined together to form a compound plate.
The thickness of plates are
4.0
cm
and
2.5
cm
respectively and the area of cross-section is
120
cm
2
for each plate. The equivalent thermal conductivity of the compound plate is
(
1
+
5
α
)
K
, then the value of
α
will be______
[29-Jun-2022-Shift-1]
Your Answer:
Validate
Solution:
L
1
K
1
A
1
+
L
2
K
2
A
2
=
L
1
+
L
2
K
eff
A
eff
⇒
4
K
+
2.5
2
K
=
6.5
K
eff
⇒
10.5
2
K
=
6.5
K
eff
⇒
K
e
f
f
=
13
K
10.5
=
(
1
+
5
21
)
K
⇒
α
=
21
© examsnet.com
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