Concept:Work done by an external agent to change the configuration is equal to the change in the gravitational potential energy of the system.Formula:For three masses m1,m2,m3 at vertices of an equilateral triangle of side L,U=−LG(m1m2+m2m3+m3m1)W=Ufinal−UinitialSolution:Compute the sum of products:200×300+300×400+400×200=60000+120000+80000=2.6×105kg2Initial side Li=20m, final side Lf=25mW=G(2.6×105)(Li1−Lf1)201−251=1005−4=1001=1×10−2Substitute G=6.7×10−11Nm2/kg2:W=(6.7×10−11)×(2.6×105)×(1×10−2)=6.7×2.6×10−8=17.42×10−8=1.74×10−7J