The diagram and the required components of force on given block are shown below
From the above diagram, N=mg−Fsinθ...(i) where, N= normal force and Fcosθ−fk=ma⇒Fcosθ−μkN=ma ...(ii) where, fk= kinetic friction force. From Eq. (i) and Eq. (ii), we get Fcosθ−μk(mg−Fsinθ)=ma⇒a=mFcosθ−μk(g−mFsinθ) This is the required acceleration of the block.
