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Laws of Motion Part 1

Section: Physics

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Question : 89 of 100

Marks: +1, -0

Three forces start acting simultaneously on a particle moving with velocity,

\vec{v}

. These forces are represented in magnitude and direction by the three sides of a triangle

A B C

. The particle will now move with velocity

less than $\vec{v}$
greater than $\vec{v}$
$|v|$ in the direction of the largest force $B C$
$\vec{v}$ , remaining unchanged

Solution:

As shown in the figure, the three forces are represented by the sides of a triangle taken in the same order. So the particle will be in equilibrium under the three forces.

Therefore the resultant force is zero.

We know,

\vec{F}\;\text{net}\;=\vec{ma}

\therefore 0=\vec{ma}

\Rightarrow \vec{a}=0

Therefore acceleration will be zero.

Hence the particle velocity remains unchanged.

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