The co-ordinates of a particle moving in x-y plane are given by : x=2+4 t, y=3 t+8 t² . The motion of the particle is : [4 Apr 2024 Shift 1]

Correct Answer is : uniformly accelerated having motion along a parabolic path.

uniformly accelerated having motion along a straight line.

uniform motion along a straight line.

uniformly accelerated having motion along a parabolic path.

Correct Answer is : uniformly accelerated having motion along a parabolic path.

Test Index

Motion in a Plane

Section: Physics

Question : 25 of 94

Marks: +1, -0

x-y

x=2+4 t, y=3 t+8 t^2 .

Solution: 👈: Video Solution

\;x=2+4 t

\;\;\frac{d x}{d t}=v_x=4

\;\;\frac{d v_x}{d t}=a_x=0

\;y=3 t+8 t^2

\;\;\frac{d y}{d t}=v_y=3+16 t

\;\;\frac{d v_y}{d t}=a_y=16

the motion will be uniformly accelerated motion.

For path

\; x=2+4 t

\;\;\frac{x-2}{4}= t

Put this value of

t

is equation of

y=3 \left(\;\frac{x-2}{4}\right) +8 \left(\;\frac{x-2}{4}\right)^2

y=3 (\;{x-2}/{4}) +8 (\;{x-2}/{4}) ^2

this is a quadratic equation so path will be parabola.

Correct answer (4)

Go to Question:

Prev Question

Next Question