(I) Adiabatic process ⇒ΔQ=0 No exchange of heat takes place with surroundings (II) Isothermal proess ⇒ Temperature remains constant (ΔT=0)Δu=2FnRΔT⇒Δu=0 No change in internal energy [Δu=0] (III) Isochoric process Volume remains constant ΔV=0W=∫P⋅dV=0 Hence work done is zero. (IV) Isobaric process ⇒ Pressure remains constant W=P⋅ΔV=0Δu=2FnRΔT=2F[PΔV]=0ΔQ=nCpΔT=0