Test Index

Waves Part 1

Section: Physics

Question : 91 of 100

Marks: +1, -0

When two tuning forks (fork 1 and fork 2 ) are sounded simultaneously, 4 beats per second are heated. Now, some tape is attached on the prong of the fork 2 . When the tuning forks are sounded again, 6 beats per second are heard. If the frequency of fork 1 is

200\,\text{Hz}

, then what was the original frequency of fork 2 ?

[AIEEE 2005]

202 Hz
200 Hz
204 Hz
196 Hz

Validate

Solution:

No. of beats heard when fork 2 is sounded with fork

1=\Delta n=4

Now we know that if on loading (attaching tape) an unknown fork, the beat frequency increases (from 4 to 6 in this case) then the frequency of the unknown fork 2 is given by,

n=n_0-\Delta n=200-4=196\,\text{Hz}

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