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JEE Main Physics Class 12 Current Electricity Part 3 Questions
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© examsnet.com
Question : 3
Total: 100
Two cells are connected in opposition as shown. Cell
E
1
is of
8
V
emf and
2
Ω
internal resistance; the cell
E
2
is of
2
V
emf and
4
Ω
internal resistance. The terminal potential difference of cell
E
2
is:
[30-Jan-2024 Shift 1]
Your Answer:
Validate
Solution:
👈: Video Solution
I
=
8
−
2
2
+
4
=
6
6
=
1
A
Applying Kirchhoff from C to B
V
C
−
2
−
4
×
1
=
V
B
V
C
−
V
B
=
6
V
=
6
V
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