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JEE Main Physics Class 12 Electromagnetic Waves Part 1 Questions

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Question : 45

Total: 100

For a plane electromagnetic wave, the magnetic field at a point x and time t is

(x,t)=[1.2×10−7‌sin(0.5×103x +1.5×1011t)‌

]‌T
The instantaneous electric field

corresponding to B is: ( speed of light c=3×108ms−1)

[Sep. 06, 2020 (II)]

→
E
(x,t)=[−36‌sin(0.5×103x +1.5×1011t)‌
^
j
]‌
V
m
→
E
(x,t)=[36‌sin(1×103x +0.5×1011t)‌
^
j
]‌
V
m
→
E
(x,t)=[36‌sin(0.5×103x +1.5×1011t)‌
^
k
]‌
V
m
→
E
(x,t)=[36‌sin(1×103x +0.5×1011t)‌
^
i
]‌
V
m

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