Test Index

JEE Main Physics Class 12 Electromagnetic Waves Part 2 Questions

© examsnet.com

Question : 12

Total: 24

The electric field of an electromagnetic wave in free space is represented as

=E0‌cos(ωt−kz)‌

.
The corresponding magnetic induction vector will be :

[30-Jan-2024 Shift 1]

→
B
=E0C‌cos(ωt−kz)‌
^
j
→
B
=‌
E0
C
‌cos(ωt−kz)‌
^
j
→
B
=E0‌Cos(ωt+kz)‌
^
j
→
B
=‌
E0
C
‌cos(ωt+kz)‌
^
j

Go to Question:

Prev Question

Next Question