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JEE Main Physics Class 12 Electromagnetic Waves Part 2 Questions
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© examsnet.com
Question : 3
Total: 24
An alternating voltage of amplitude
40
V
and frequency
4
kHz
is applied directly across the capacitor of
12
µ
F
. The maximum displacement current between the plates of the capacitor is nearly:
[5 Apr 2024 Shift 1]
13
A
8
A
10
A
12
A
Validate
Solution:
👈: Video Solution
Displacement current is same as conduction current in capacitor.
X
C
=
1
ω
C
=
1
2
π
fC
=
1
2
π
×
4
×
10
3
×
12
×
10
−
6
=
3.317
Ω
I
=
V
X
C
=
40
3.317
=
12
A
© examsnet.com
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