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JEE Main Physics Class 12 Electromagnetic Waves Part 2 Questions
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© examsnet.com
Question : 8
Total: 24
The magnetic field in a plane electromagnetic wave is
B
y
=
(
3.5
×
10
−
7
)
s
i
n
(
1.5
×
10
3
x
+
0.5
.
×
10
11
t
)
T
. The corresponding electric field will be
[9 Apr 2024 Shift 2]
E
y
=
1.17
s
i
n
(
1.5
×
10
3
x
+
0.5
×
10
11
t
)
Vm
−
1
E
z
=
105
s
i
n
(
1.5
×
10
3
x
+
0.5
×
10
11
t
)
Vm
−
1
E
z
=
1.17
s
i
n
(
1.5
×
10
3
x
+
0.5
×
10
11
t
)
Vm
−
1
E
y
=
10.5
s
i
n
(
1.5
×
10
3
x
+
0.5
×
10
11
t
)
Vm
−
1
Validate
Solution:
👈: Video Solution
E
0
=
B
0
C
E
0
=
3
×
10
8
×
(
3.5
×
10
−
7
)
s
i
n
(
1.5
×
10
3
x
+
0.5
×
10
11
t
)
E
0
=
105
s
i
n
(
1.5
×
10
3
x
+
0.5
×
10
11
t
)
Vm
−
1
Data inconsistent while calculating speed of wave. You can challenge for data.
© examsnet.com
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