Electromagnetic Waves Part 1

Given, frequency, $f=500 \text{MHz}=5 \times 10^{8} \text{Hz}$ $B=8.0 \times 10^{-8} \hat{Z} \text{T}$ $\therefore$ Magnitude of peak value of magnetic field is given by $B_0=8 \times 10^{-8} \text{T}$ We know that, $\;\frac{E_0}{B_0}=C$ where, $E_0$ is the magnitude of peak value of electric field and $c$ is the speed of electromagnetic wave in air (or vacuum). $\Rightarrow \;\; E_0=c B_0$ $=3 \times 10^{8} \times 8 \times 10^{-8}=24 \text{V/m}$ Since, the direction of propagation of electromagnetic wave is perpendicular to the direction of $E$ and $B$ both. $\therefore$ Direction of propagation is given by $\hat{E} \times \hat{B}$. As, the wave is travelling in $y$-direction, and the magnetic field is in z-direction. $\Rightarrow \hat{E} \times \hat{z} \;\; = \hat{y}$ $\hat{E} \;\; = -\hat{x}$ $\therefore$ The value of electric field will be $-24 \hat{x} \text{V/m}$.