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Electrostatics Part 1

Section: Physics

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Question : 83 of 100

Marks: +1, -0

An electric charge

10^{-3} \mu \mathrm{C}

is placed at the origin

(0,0)

X-Y

co-ordinate system. Two points

A

B

are situated at

(\sqrt{2}, \sqrt{2})

(2,0)

respectively. The potential difference between the points

A

B

$4.5$ volts
$9$ volts
zero
$2$ volts

Solution:

The distance of point

A(\sqrt{2}, \sqrt{2})

from the origin,

OA = |\vec{r}_1|

=\sqrt{(\sqrt{2})^2+(\sqrt{2})^2}

=\sqrt{4}=2

The distance of point

B(2,0)

from the origin,

OB = |\vec{r}_2| = \sqrt{(2)^2+(0)^2} = 2

units.

Now, potential at

A, V_A = \frac{1}{4\pi E_0} \cdot \frac{Q}{OA}

Potential at

B, V_B = \frac{1}{4\pi E_0} \cdot \frac{Q}{Ob}

\therefore

Potential difference between the points

A

and

B

is zero.

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