Electrostatics Part 2

Net charge on electyric dipole $=+q-q=0$ Hence, according to Gauss's law, Electric flux, $\phi = \frac{q_{\text{net}}}{\varepsilon_0} = \frac{0}{\varepsilon_0} = 0$ Electric field due to electric dipole is non-zero and varies at point to point. Hence, statement $I$ is true. Electric field due to charged solid sphere at a distance $r$ from centre. $E = \frac{1}{4 \pi \varepsilon_0} \cdot \frac{Q r}{R^{3}} \left[ \begin{array}{c} \text{when } r < R \\ R \rightarrow \text{radius} \end{array} \right]$ which is non-zero. Hence, statement II is false. Hence, option (b) is the correct.