Option (A) W=kf−kjqE(2a−0)=21m(2V)2−21mV2qE2a=23mV2E=43qamv2 Option (B) Rate of work done P =F⋅V=FVcosθ=FV Power = qEV =q(43qamV2)V=q43qamV3=43amV3 Option (C)Angle between electric force and velocity is 90°, hence rate of work done will be zero at Q.Option (D)Initial angular momentum Li=mVaFinal angular momentum Lf=m(2V)(2a)Change in angular momentum Lf−Li=3mVa(Note : angular momentum is calculated about O)