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Wave Optics Part 2

Section: Physics

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Question : 11 of 77

Marks: +1, -0

An unpolarized light is incident on the plane interface of air-dielectric medium shown in figure. If the incident angle is equal to Brewster angle, identify the expression representing reflected wave.

[JEE Main 4 Apr 2026 Shift 1]

$(E_x \hat{i} + E_y \hat{j}) \sin (kx - kz - \omega t)$
$(E_x \hat{i} + E_z \hat{k}) \sin (k x + k y - \omega t)$
$(E_x \hat{j} + E_y \hat{k}) \sin (k y + k z - \omega t)$
$(E_x \hat{i} + E_y \hat{j} + E_z \hat{k}) \sin (kx + ky - kz - \omega t)$

Solution:

Is the light is propagating along the positive z-axis and its is reflected from plane then correct phase for reflected light is

kx\, - kz\, - \omega t

and for electric field as the light incident on Brewster angle so the reflected light should be perfectly plane polarized that's why polarization direction should be y-axis so electric field of reflected light contain no z-component.

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