Wave Optics Part 2

Concept:When unpolarized light is incident at Brewster's angle, the reflected light is completely polarized.At this angle, the reflected and refracted rays are perpendicular to each other.Explanation:Given: refractive index of glass $\mu = 1.52$, air $\mu_0 = 1.00$.Brewster's angle $i_p$ satisfies $\tan i_p = \frac{\mu}{\mu_0}$.So $\tan i_p = 1.52$, hence $i_p = \tan^{-1}(1.52) = 57.7^\circ$.From the perpendicular condition: $i_p + \theta_r' = 90^\circ$, where $\theta_r'$ is the angle of refraction.Thus $\theta_r' = 90^\circ - i_p = 90^\circ - 57.7^\circ = 32.3^\circ$.Answer:The angle of the refracted beam is $32.3^\circ$. The correct option is D.