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JEE Mains 02-Sep-2020 Shift 1 Solved Paper
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© examsnet.com
Question : 24
Total: 75
A circular coil of radius
10
c
m
is placed in a uniform magnetic field of
3.0
×
10
−
5
T
with its plane perpendicular to the field initially. It is rotated at constant angular speed about an axis along the diameter of coil and perpendicular to magnetic field so that it undergoes half of rotation in
0.2
s
. The maximum value of EMF induced (in
µ
V
) in the coil will be close to theinteger ______.
[2 Sep 2020 Shift 1]
Your Answer:
Validate
Solution:
r
=
0.1
m
‌
‌
‌
T
2
=
0.2
s
e
c
B
=
3
×
10
−
5
m
‌
‌
‌
T
=
0.4
s
e
c
At any time flux
Ï•
=
B
A
‌
cos
‌
ω
‌
t
|
emf
|
=
|
d
Ï•
d
t
|
=
|
B
A
ω
‌
sin
‌
ω
‌
t
|
(
emf
)
max
=
B
A
ω
=
B
A
2
Ï€
T
=
3
×
10
−
5
×
Ï€
×
(
0.1
)
2
×
2
Ï€
0.4
=
6
Ï€
2
4
×
10
−
6
‌
‌
‌
‌
(
Ï€
2
≃
10
‌
take
)
=
15
×
10
−
6
=
15
µ
V
© examsnet.com
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