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JEE Mains 02-Sep-2020 Shift 2 Solved Paper
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© examsnet.com
Question : 2
Total: 75
The displacement time graph of a particle executing S.H.M. is given in figure :
(sketch is schematic and not to scale)
Which of the following statements is/are true for this motion?
(A) The force is zero
t
=
3
T
4
(B) The acceleration is maximum at
t
=
T
(C) The speed is maximum at
t
=
T
4
(D) The P.E. is equal to K.E. of the oscillation at
t
=
T
2
(
A
)
,
(
B
)
and
(
D
)
(
B
)
,
(
C
)
and
(
D
)
(A) and (D)
(
A
)
,
(
B
)
and
(
C
)
Validate
Solution:
(
A
)
F
=
m
a
a
=
−
ω
2
x
at
3
T
4
displacement zero
(
x
=
0
)
,
so
a
=
0
F
=
0
(B) at
t
=
T
displacement
(
x
)
=
A
x maximum, So acceleration is maximum.
(C)
V
=
ω
√
A
2
−
x
2
V
max
at
x
=
0
V
max
=
A
ω
at
t
=
T
4
,
x
=
0
,
So
V
max
(D)
K
E
=
P
E
∴
at
x
=
A
√
2
at
t
=
T
2
x
=
−
A
(So not possible)
© examsnet.com
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