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JEE Mains 04-Sep-2020 Shift 2 Solved Paper
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© examsnet.com
Question : 3
Total: 75
A capacitor
C
is fully charged with voltage
V
0
. After disconnecting the voltage source, it is connected in parallel with another uncharged capacitor of capacitance
C
2
.
The energy loss in the process after the charge is distributed between the two capacitors is :
1
6
C
V
0
2
1
2
C
V
0
2
1
3
C
V
0
2
1
4
C
V
0
2
Validate
Solution:
C
V
0
−
q
C
=
q
C
∕
2
=
2
q
C
V
0
=
3
q
C
⇒
q
=
C
V
0
3
U
i
=
1
2
C
V
0
2
U
f
=
(
2
C
V
0
3
)
2
2
C
+
(
C
V
0
3
)
2
2
(
C
2
)
=
1
2
C
V
0
2
[
4
9
+
2
9
]
=
1
2
C
V
0
2
(
2
3
)
Heat loss
=
1
2
C
V
0
2
−
(
2
3
)
(
1
2
C
V
0
2
)
=
1
6
C
V
0
2
© examsnet.com
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