In the circuit shown, charge on the 5\;{F} capacitor is : [5 Sep 2020 Shift 2]

Correct Answer is : 16.36 μC16.36\;{C}16.36μC

Correct Answer is : 16.36 μC16.36\;{C}16.36μC

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JEE Mains 05 Sep 2020 Shift 2 Solved Paper

Section: Physics

Question : 12 of 75

Marks: +1, -0

5\;\mu\mathrm{F}

Solution:

Let potential of point

O\;\;\;\;v_0=0

Now, using junction analysis

We can say,

q_1+q_2+q_3=0

2(x-6)+4(x-6)+5(x)=0

x=\frac{36}{11}\;\;\;q_3=\frac{36(5)}{11}=\frac{180}{11}

q_3=16.36\;\mu\mathrm{C}

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