Examsnet
Unconfined exams practice
Home
Exams
Banking Entrance Exams
CUET Exam Papers
Defence Exams
Engineering Exams
Finance Entrance Exams
GATE Exam Practice
Insurance Exams
International Exams
JEE Exams
LAW Entrance Exams
MBA Entrance Exams
MCA Entrance Exams
Medical Entrance Exams
Other Entrance Exams
Police Exams
Public Service Commission (PSC)
RRB Entrance Exams
SSC Exams
State Govt Exams
Subjectwise Practice
Teacher Exams
SET Exams(State Eligibility Test)
UPSC Entrance Exams
Aptitude
Algebra and Higher Mathematics
Arithmetic
Commercial Mathematics
Data Based Mathematics
Geometry and Mensuration
Number System and Numeracy
Problem Solving
Board Exams
Andhra
Bihar
CBSE
Gujarat
Haryana
ICSE
Jammu and Kashmir
Karnataka
Kerala
Madhya Pradesh
Maharashtra
Odisha
Tamil Nadu
Telangana
Uttar Pradesh
English
Competitive English
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Careers
Contact Us
Our Apps
Privacy
Test Index
JEE Mains 05-Sep-2020 Shift 2 Solved Paper
Show Para
Hide Para
Share question:
© examsnet.com
Question : 23
Total: 75
A thin rod of mass
0.9
k
g
and length
1
m
is suspended, at rest, from one end so that it can freely oscillate in the vertical plane. A particle of move
0.1
k
g
moving in a straight line with velocity
80
m
∕
s
hits the rod at its bottom most point and sticks to it (see figure). The angular speed (in rad/s) of the rod immediately after the collision will be ______.
Your Answer:
Validate
Solution:
→
L
i
=
→
L
f
m
v
L
=
I
ω
m
v
L
=
(
M
L
2
3
+
m
L
2
)
ω
0.1
×
80
×
1
=
(
0.9
×
1
2
3
+
0.1
×
1
2
)
ω
8
=
(
3
10
+
1
10
)
ω
8
=
4
10
ω
ω
=
20
rad
rad
sec
© examsnet.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
Prev Question
Next Question